((0.43-x)(0.25-x))/(2x)^2=

Solution for ((0.43-x)(0.25-x))/(2x)^2= equation:

((0.43-x)(0.25-x))/(2x)^2=

We move all terms to the left:

((0.43-x)(0.25-x))/(2x)^2-()=0


Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

((-1x+0.43)(-1x+0.25))/2x^2-()=0

We add all the numbers together, and all the variables

((-1x+0.43)(-1x+0.25))/2x^2=0

We multiply parentheses ..

((+x^2-0.25x-0.43x+0.1075))/2x^2=0

We multiply all the terms by the denominator


((+x^2-0.25x-0.43x+0.1075))=0


We calculate terms in parentheses: +((+x^2-0.25x-0.43x+0.1075)), so:

(+x^2-0.25x-0.43x+0.1075)

We get rid of parentheses

x^2-0.25x-0.43x+0.1075

We add all the numbers together, and all the variables

x^2-0.68x+0.1075

Back to the equation:

+(x^2-0.68x+0.1075)


We get rid of parentheses

x^2-0.68x+0.1075=0

a = 1; b = -0.68; c = +0.1075;
Δ = b2-4ac
Δ = -0.682-4·1·0.1075
Δ = 0.0324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.68)-\sqrt{0.0324}}{2*1}=\frac{0.68-\sqrt{0.0324}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.68)+\sqrt{0.0324}}{2*1}=\frac{0.68+\sqrt{0.0324}}{2}
$